博客
关于我
HDU1595(最短路 + 枚举)
阅读量:228 次
发布时间:2019-02-28

本文共 2813 字,大约阅读时间需要 9 分钟。

?????????????1??n??????????????????????????????????????????????????????????????

????

????????1??n????????????????????????????????????????????????????????????

  • ????1??n??????
  • ?????????? - ??????????
  • ????

    ????????????????????

  • ??????????????????????????????????????????????

  • ?????????????????????????????????????????????????????????0?????????????

  • Dijkstra?????????????????????Dijkstra???????1??n??????????????????????????????????????????????????????????????

  • ?????????Dijkstra?????????????????????????????????????????????????????

  • ????????????????????????????????????????????????????????????????-1?

  • ????

    ?????????C++???

    #include 
    #include
    #include
    #include
    #include
    using namespace std;const int inf = 1 << 30;const int maxn = 1005;const int maxm = 1e6 + 1e4;struct edge { int to; int w; int h; int next;};struct Node { int k, s; Node(int a, int b) { k = a; s = b; } bool operator<(const Node a) const { return s < a.s; }};int dijkstra(int s, int t, int x) { int dist[s + 1]; fill(dist, dist + s + 1, inf); dist[s] = 0; priority_queue
    q; q.push(Node(s, 0)); int visited[s + 1] = {0}; while (!q.empty()) { Node p = q.top(); q.pop(); if (visited[p.k]) continue; visited[p.k] = 1; for (int i = head[p.k]; i != -1; i = e[i].next) { edge f = e[i]; if (f.h != -1 && f.h < x) continue; if (dist[f.to] > dist[p.k] + f.w) { dist[f.to] = dist[p.k] + f.w; q.push(Node(f.to, dist[f.to])); } } } return (dist[t] == inf) ? -1 : dist[t];}int main() { int t; scanf("%d", &t); while (t--) { int n, m; scanf("%d", &n); scanf("%d", &m); int height[n + 1]; for (int i = 1; i <= n; ++i) { scanf("%d", &height[i]); } edge e[maxm * 2]; int head[n + 1] = {-1}; int cnt = 0; for (int i = 0; i < m; ++i) { int x, y, z, c; scanf("%d", &x); scanf("%d", &y); scanf("%d", &z); scanf("%d", &c); addedge(x, y, z, c); addedge(y, x, z, c); } int l = 0, r = height[1] - height[n]; int max_height = -1; int max_length = 0; while (l <= r) { int mid = l + (r - l) / 2; int current_max_height = mid; int ans = dijkstra(1, n, current_max_height); if (ans != -1) { if (current_max_height > max_height) { max_height = current_max_height; max_length = ans; } l = mid + 1; } else { r = mid - 1; } } if (max_height == -1) { puts("cannot reach destination"); } else { puts("maximum height = " + to_string(max_height)); puts("length of shortest route = " + to_string(max_length)); } }}

    ????

  • ?????

    • edge ???????????????????????????????
    • Node ??????????????????????????????
  • Dijkstra???

    • ?????????Dijkstra???????????????????????
    • ?????????????????????????????
  • ?????

    • ???????????????????????????????
  • ?????

    • ????????????????????????????
  • ??

    ??????????????????1??n????????????????????Dijkstra?????????????????????????????????????????

    转载地址:http://thep.baihongyu.com/

    你可能感兴趣的文章
    Qt知识:视图框架QGraphicsWidget详解
    查看>>
    SpringBoot中项目启动及定时任务缓存数据库常用数据至内存变量并转换后高频调用
    查看>>
    Qt知识: 画刷风格
    查看>>
    QT的OpenGL渲染窗QOpenGLWidget Class
    查看>>
    QT的C++程序加载动态链接库DLL(Linux下是so)的方式
    查看>>
    QT界面操作1:如何跟踪鼠标位置?
    查看>>
    Qt环境搭建(Visual Studio)
    查看>>
    QT点击"X"按钮,调用closeEvent()函数来实现调用特定事件(附:粗略介绍QT的信号与槽的使用方法)...
    查看>>
    QT样式表——url路径
    查看>>
    QT数据库(三):QSqlQuery使用
    查看>>
    QT教程5:消息框
    查看>>
    SpringBoot中集成阿里开源缓存访问框架JetCache实现声明式实例和方法缓存
    查看>>
    pom.xml中提示web.xml is missing and <failonmissingw>...
    查看>>
    Pomelo开发中Web客户端开发API简介
    查看>>
    QT教程2:QT5的体系构架
    查看>>
    PON架构(全光网络)
    查看>>
    PoolingHttpClientConnectionManager原理剖析
    查看>>
    QT教程1:ubuntu18.04安装QT5
    查看>>
    POP-一个点击带有放大还原的动画效果
    查看>>
    POP3 协议在计算机网络中的优缺点
    查看>>